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∫x23−xdx
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Solution
−3−xx2ln(3)−2ln2(3)·3−xx−2ln3(3)·3−x+C
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Solution steps
Solve by:
One step at a time
∫x2·3−xdx
Apply u-substitution:∫−3uu2du
=∫−3uu2du
Take the constant out: ∫a·f(x)dx=a·∫f(x)dx
=−∫3uu2du
Apply Integration By Parts:3uu2ln(3)−∫2·3uuln(3)du