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diretriz y=3a^2+1-(4+2a^2)

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`x`²	`x`^□	log_□	√☐	^□√☐	≤	≥	□□	·	÷	`x`^◦	π
(☐)^′	`ddx`	∂∂`x`	∫	∫_□^□	lim	∑	∞	`θ`	(`f` ◦ `g`)	`f`(`x`)

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≥	≤	·	÷	`x`^◦	(☐)	\|☐\|	(`f` ◦ `g`)	`f`(`x`)	ln	`e`^☐
(☐)^′	∂∂`x`	∫_□^□	lim	∑	sin	cos	tan	cot	csc	sec

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inverse 3a²+1−(4+2a²)

Solution

√a+3, −√a+3

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Function Inverse definition

A function g is the inverse of function f if for y=f(x), x=g(y)

y=3a²+1−(4+2a²)

Replace a with y

a=3y²+1−(4+2y²)

Solve for y, a=3y²+1−(4+2y²)

√a+3, −√a+3

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domain 3a²+1−(4+2a²)

range 3a²+1−(4+2a²)

vertices 3a²+1−(4+2a²)

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−▭▭	<	7	8	9	÷	`AC`
+▭▭	>	4	5	6	×	☐☐☐
×▭▭	(	1	2	3	−	`x`
▭ \|▭	)	.	0	=	+	`y`

diretriz y=3a^2+1-(4+2a^2)

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diretriz y=3a^2+1-(4+2a^2)

Solution

Solution steps

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