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interceptos sqrt(x^2+1)

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`x`²	`x`^□	log_□	√☐	^□√☐	≤	≥	□□	·	÷	`x`^◦	π
(☐)^′	`ddx`	∂∂`x`	∫	∫_□^□	lim	∑	∞	`θ`	(`f` ◦ `g`)	`f`(`x`)

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≥	≤	·	÷	`x`^◦	(☐)	\|☐\|	(`f` ◦ `g`)	`f`(`x`)	ln	`e`^☐
(☐)^′	∂∂`x`	∫_□^□	lim	∑	sin	cos	tan	cot	csc	sec

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range (x²+2x−1)· (2x²−3x+6)

Solution

f(x)≥ −26.25679…

Interval Notation

[−26.25679…, ∞ )

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Function range definition

The set of values of the dependent variable for which a function is defined

Find the minimum and maximum value in each defined interval and unite the results

Domain of (x²+2x−1)· (2x²−3x+6) : −∞ <x<∞

Extreme Points of (x²+2x−1)· (2x²−3x+6): Minimum(−1.51802…, −26.25679…)

Find the range for the interval −∞ <x<∞ : −26.25679…≤ f(x)<∞

Combine the ranges of all domain intervals to obtain the function range

f(x)≥ −26.25679…

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domain (x²+2x−1)· (2x²−3x+6)

inverse (x²+2x−1)· (2x²−3x+6)

intercepts (x²+2x−1)· (2x²−3x+6)

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−▭▭	<	7	8	9	÷	`AC`
+▭▭	>	4	5	6	×	☐☐☐
×▭▭	(	1	2	3	−	`x`
▭ \|▭	)	.	0	=	+	`y`

interceptos sqrt(x^2+1)

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interceptos sqrt(x^2+1)

Solution

Solution steps

Solve instead

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