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area x^2+(y+3)^2=16

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`x`²	`x`^□	log_□	√☐	^□√☐	≤	≥	□□	·	÷	`x`^◦	π
(☐)^′	`ddx`	∂∂`x`	∫	∫_□^□	lim	∑	∞	`θ`	(`f` ◦ `g`)	`f`(`x`)

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ddx

≥	≤	·	÷	`x`^◦	(☐)	\|☐\|	(`f` ◦ `g`)	`f`(`x`)	ln	`e`^☐
(☐)^′	∂∂`x`	∫_□^□	lim	∑	sin	cos	tan	cot	csc	sec

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bernoulli x²dydx =y²

Solution

y=x1+c₁x

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Definição de imagem de função

O conjunto de valores da variável dependente para a qual uma função é definida

A imagem da função é o domínio combinado das funções inversas

Encontrar a(s) função(ões) inversa(s) de: 2a³· 4a³

Inversa de 2a³· 4a³: ⁶√a8 , −⁶√a8

⁶√a8 , −⁶√a8

Encontrar o domínio de cada função inversa

Domínio de ⁶√a8 : a≥ 0

Domínio de −⁶√a8 : a≥ 0

Combinar os intervalos

f(x)≥ 0

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−▭▭	<	7	8	9	÷	`AC`
+▭▭	>	4	5	6	×	☐☐☐
×▭▭	(	1	2	3	−	`x`
▭ \|▭	)	.	0	=	+	`y`

area x^2+(y+3)^2=16

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area x^2+(y+3)^2=16

Solution

Solution steps

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