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∫(x3−21x)(5+4x−x2)dx
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Solution
−x22−4x+20(16ln|x+1|−16ln|x−5|)+C
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Solve by:
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∫x3−21x5+4x−x2dx
Divisão longa x3−21x5+4x−x2:−x−4+20−x2+4x+5
=∫−x−4+20−x2+4x+5dx
Aplicar a regra da soma: ∫f(x)±g(x)dx=∫f(x)dx±∫g(x)dx