y-intercept f(x)=ln(x-5)

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`x`²	`x`^□	log_□	√☐	^□√☐	≤	≥	□□	·	÷	`x`^◦	π
(☐)^′	`ddx`	∂∂`x`	∫	∫_□^□	lim	∑	∞	`θ`	(`f` ◦ `g`)	`f`(`x`)

☐²

x^☐

√☐

^□√☐

□□

log_□

θ

∞

∫

ddx

≥	≤	·	÷	`x`^◦	(☐)	\|☐\|	(`f` ◦ `g`)	`f`(`x`)	ln	`e`^☐
(☐)^′	∂∂`x`	∫_□^□	lim	∑	sin	cos	tan	cot	csc	sec

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comprimento do arco ln(sec(x)), [0, π4 ]

Solution

ln(1+√2)

Decimal

0.88137…

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Definição de comprimento de arco de uma função

O comprimento de arco de uma função é o comprimento de uma curva f(x) em um intervalo [a, b] dado por
L=∫_a^b√1+(f ′(x))²dx

Aplique a fórmula do comprimento de arco: ∫₀^π4√sec²(x)dx

Resolver ∫₀^π4√sec²(x)dx: ln(1+√2)

O comprimento de arco é:

=ln(1+√2)

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−▭▭	<	7	8	9	÷	`AC`
+▭▭	>	4	5	6	×	☐☐☐
×▭▭	(	1	2	3	−	`x`
▭ \|▭	)	.	0	=	+	`y`

y-intercept f(x)=ln(x-5)

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